1. The problem statement, all variables and given/known data four point charges are placed at the corners of a square as shown in the figure having side 10 cm.If q is 1μC then what will be electric field intensity at the centre of the square? 2. Relevant equations 3. The attempt at a solution Half of diagonal a/√2 0.1/√2 Electric field due to charge "q" =9 ×10^9 ×1×10^-6/(0.1/√2 )^2=18×10^5 But the thing I m not getting is In the solution it has been given that at center there are two electric field which are perpendicular to each other.I want to know how?