A uniform electric field of magnitude 375 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. After the electron has moved 3.2 cm, what is
a. the work done by the field on the electron
b. change in potential energy associated with the electron
c. velocity of the electron
W = -qEd
KE = 1/2 mv^2
The Attempt at a Solution
As far as math goes, I got all the answers, but I do not have the signs correct.
a. 1.92 x 10^-18 joules
b. -1.92 x 10^-18 joules
c. -2.05 x 10^6 m/s
I got those numbers, but the signs are entirely wrong. My book doesn't explain things very clearly. But what I'm confused about, is when an E field is pointing to the right, doesn't that mean the electron should move to the right? What does negative work mean? How does the electron lose potential energy?