Potential Difference in Circuits

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 2K views
DriggyBoy
Messages
19
Reaction score
0
In the picture that i attached
i need some help
********
In the book it says
''' The negative terminal of the battery E_1 is connected to b. So at the lower end of the resistance R_2 the pd is 6V. "'
What is the significance of this statement?
 

Attachments

  • physx_forums.png
    physx_forums.png
    5.1 KB · Views: 556
Last edited:
Physics news on Phys.org
where's the picture?
 
R_1 is 2 ohm
nd R_2 is 4 ohm
 
I just can't grasp what you are getting at. Are you saying why the pd between the negative end of E1 and the lower end of resistor R2 is claimed to be 6v?
 
DriggyBoy said:
In the picture that i attached
i need some help
********
In the book it says
''' The negative terminal of the battery E_1 is connected to b. So at the lower end of the resistance R_2 the pd is 6V. "'
What is the significance of this statement?

The statement is a bit sloppy because it uses "PD", which should explicitly specify two points in the circuit, between which there is a Difference in Potential.
If E2 is a 6V battery then, relative to point b, how can the Potential be anything but 6V? It's just stating the obvious, really, and can be used as a start in calculating the current and volts around the network.