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Potential difference in uniform electric field

  1. Feb 27, 2010 #1
    1. The problem statement, all variables and given/known data
    A uniform electric field of magnitude 325 V/m is directed in the negative y direction. The coordinates of point A are (-0.200, -0.300) m and those of point B are (0.400, 0.500) m. Calculate the potential difference V(B)-V(A).


    2. Relevant equations



    3. The attempt at a solution
    What I first did was that since the electric field is pointing towards the negative y direction, I think that I should use only the y component of the distance between Point A and B (0.8 m) and then use V(B)-V(A)= + E X distance. This gave me 260 V...I'm not sure but can anyone tell me if I'm doing it wrong and making a mistake somewhere?
     
  2. jcsd
  3. Feb 27, 2010 #2

    tiny-tim

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    Hi lha08! :smile:

    Method looks ok …

    electric potential = potential energy per charge,

    and potential energy is just another name for (minus) the work done, which is force "dot" distance, or E.d.

    E is in the y-direction, so E.d only uses the y-coordinate of distance (and be careful about the sign :wink:)
     
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