Potential Difference of 1200 V Gives Electron 1200 eV Kinetic Energy

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SUMMARY

An electron accelerated through a potential difference of 1200 V acquires a kinetic energy of 1200 eV. This is derived from the relationship between electric potential and kinetic energy, where the energy gained by the electron is equal to the charge of the electron multiplied by the potential difference. The formula used is 1/2mv² = qV, where q represents the charge of the electron and V is the voltage. The electron-volt (eV) is defined as the energy gained by an electron when it moves through a one-volt potential difference.

PREREQUISITES
  • Understanding of electric potential and voltage
  • Familiarity with the concept of electron-volts (eV)
  • Basic knowledge of kinetic energy equations
  • Knowledge of charge in coulombs
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  • Study the relationship between voltage and kinetic energy in charged particles
  • Learn about the derivation of the electron-volt as a unit of energy
  • Explore the implications of electric fields on particle acceleration
  • Investigate the applications of electron acceleration in particle physics
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This discussion is beneficial for physics students, electrical engineers, and anyone interested in the principles of particle acceleration and energy conversion in electric fields.

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An electron is accelerated from rest through a potential difference 1200 V. Give the electron's kinetic energy after this acceleration in electron-volts?

----I know the answer is 1200 eV but if someone could explain how to get the answer?? And how do I apply 1/2mv^2=qV
 
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The electron-volt is a unit of energy. It's the energy obtained by an electron falling through a one volt electrical potential difference.

Remember that electrical potential is measured in Volts, and that the Volt can be broken down further in terms of units:

[Volt] = \frac{[Joule]}{[Coulomb]}

The electron has a charge in coulombs. The field bestows Volt joules per coulomb when it passes through.
 

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