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The potential difference between points A and B in a circuit with 2V and 4V electromotive forces (emfs) and internal resistances of 2Ω and 6Ω respectively is determined to be 0V, indicating a short circuit condition. According to Ohm's Law (V=IR) and Kirchhoff's Laws, when resistance approaches zero, the potential difference also approaches zero, confirming that the circuit behaves as a short circuit. If the calculated potential difference is anything other than zero, it indicates a problem in the circuit configuration.
PREREQUISITESElectrical engineering students, circuit designers, and anyone involved in analyzing or troubleshooting electrical circuits will benefit from this discussion.
If VAB ≠ 0, then it would be I-i that goes to infinity.Metaleer said:AB seems to be a shortcircuit. That is a potential difference of 0, so if you end up getting that, it's nothing to worry about. If you got something other than 0, that's when you should be worried.
Basically, you can think of a shortcircuit as taking a branch with a single resistor R, and doing R → 0. From V = IR, you see that I = V/R, so if R → 0, the only way to stop I from going to infinity and being a defined finite value, is to have V = 0, that is, the potential difference across a shortcircuit vanishes.