Potential energy in 2 gravity fields

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SUMMARY

The discussion centers on the concept of potential energy in different gravitational fields, specifically comparing the Moon and Earth. The formula for gravitational potential energy, m * g * h, is highlighted, with specific values of gravitational acceleration for both celestial bodies: 1.6 m/s² for the Moon and 9.8 m/s² for Earth. A key conclusion is that potential energy cannot be directly compared between the two locations without considering the differences in gravitational fields and the reference points for zero potential energy. The discussion emphasizes that the gravitational field is not homogeneous at large scales, which complicates direct comparisons.

PREREQUISITES
  • Understanding of gravitational potential energy formula (m * g * h)
  • Basic knowledge of gravitational acceleration values (1.6 m/s² for Moon, 9.8 m/s² for Earth)
  • Familiarity with concepts of gravitational fields and their homogeneity
  • Awareness of reference points for potential energy comparisons
NEXT STEPS
  • Research the concept of gravitational potential energy in non-homogeneous fields
  • Study the differences in gravitational fields between celestial bodies
  • Explore the implications of reference points in potential energy calculations
  • Learn about the effects of changing gravitational fields on energy during transport
USEFUL FOR

Students of physics, educators explaining gravitational concepts, and anyone interested in the comparative analysis of potential energy in different gravitational environments.

flm
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Hi everyone,

First, sorry if the question is stupid, I do not have any background
in Physics. Just very curious.

Potential energy due to gravity is:
m * g * h Joules

Now, suppose I lift a weight on Moon at a given height. I will have:
1.6 * m * h Joules

I maintain it at that height and go to Earth. There, I will have:
9.8 * m * h Joules

Where does the added energy come from ? I cannot see why it would
come from the Moon Earth travel itself, as only the mass matters during
the motion ...

Thanks for your time and answers !

Cheers,

Fabien.
 
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First of all, the mgh formula is only a valid approximation as long as the gravitational field may be considered homogeneous. At scales as large as the distance from the gravitational center, this is no longer true.

flm said:
I maintain it at that height and go to Earth.
You cannot do this. In order to transport it to Earth, it needs to change its height from both the lunar surface and the Earth's surface. This involves a change under which the gravitational field most certainly is not homogeneous. In addition, the zero-point of the different potentials are chosen differently. You are comparing apples and carrots.
 

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