- #1

benrogers7511

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Coulombic Potential: [tex]\phi[/tex] = q/(4[tex]\pi[/tex][tex]\epsilon[/tex]r)

Total Energy= (Kinetic + Potential) = [-(h^2/2m)(d^2psi/dx^2) + U(x)]

Kinetic Energy Operator = -(h^2/2m)(d^2[tex]\psi[/tex]/dx^2)

I am looking for the potential energy operator