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queenspublic
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Homework Statement
A 4.8 g marble is fired vertically upward using a spring gun. The spring must be compressed 8.0 cm if the marble is to just reach a target 27 m above the marble's position on the compressed spring.
(a) What is the change in the gravitational potential energy of the marble-Earth system during the 27 m ascent?
(a) ? J
(b) What is the change in the elastic potential energy of the spring during its launch of the marble?
(b) ? J
(c) What is the spring constant of the spring?
(c) ? N/m
2. The attempt at a solution
(a)
27 - .080 = 26.92
(26.92)(9.8)(.0048) = (1/2)(.0048)v^2
v = 22.97 <<<< Isn't this the answer? But it's wrong.
(b)
(1/2)(the answer to c: ?)(.080)^2
(c)
(1/2)(.0048)(the answer to a: 22.97?)^2 + (.0048)(9.8)(.080) = (1/2)(k)(.080)^2
k = ?