The discussion centers around calculating the power consumption of a pump operating under specific conditions: a pressure of 500 kPa, a flow rate of 60 m3/h, and an efficiency of 80%. The focus is on understanding the relationship between pressure, flow rate, and power output, with participants exploring relevant equations and concepts.
Participants express varying levels of understanding regarding the relationships between pressure, flow rate, and power. There is no consensus on the correct approach to the problem, and multiple interpretations of the relevant equations are present.
Participants have not fully resolved the dependencies on definitions and assumptions related to flow rates and the application of efficiency in the power calculation. The discussion reflects uncertainty about the initial steps necessary to derive the power consumed by the pump.
The formula looks useful. What is qm?jderulo said:I believe it to be: [tex]P = q_m ρ g h_p[/tex]
mfb said:The formula looks useful. What is qm?
Instead of g and a height, you are given the pressure. How are those concepts related?
Similar enough.jderulo said:g is gravity, h isn't height but energy head..
mfb said:Similar enough.
The main idea is that you can write down a similar formula where you replace ρ, g and hp to include pressure instead of those two parameters.
I am surprised that it is the mass flow rate and not the volume flow rate.
Anyway, you need the delivered power output of the pump (that's what your formula can do).
Once you have that, you can see how you can include the 80% efficiency.
Right. You can simplify that formula, ρ and g will drop out and you are left with a simple product.jderulo said:[tex]h_p = p / ρ g[/tex]
?
Am I right in thinking the final formula would be
[tex]P = q_v ρ g (p / ρ g)[/tex]