Power dissipated in a cylindrical cavity due to a current carrying filament

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SUMMARY

The discussion focuses on calculating the power dissipated in a cylindrical cavity due to a current-carrying filament. The cavity, which is 2 meters long and perfectly conducting, is filled with a lossy dielectric, and a current of 10 A is applied. The electric field is defined as E = -z(i + j) at a frequency of 5 kHz. The Poynting vector is identified as a key concept for determining power loss, but the lack of specific values for permeability and permittivity of the lossy material presents a challenge in the calculation.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically Maxwell's equations.
  • Familiarity with the Poynting vector and its application in power calculations.
  • Knowledge of lossy dielectric materials and their properties.
  • Basic principles of cylindrical coordinates in electromagnetics.
NEXT STEPS
  • Research the calculation of power loss in lossy dielectrics using the Poynting vector.
  • Study the properties of lossy dielectric materials, including their permittivity and permeability.
  • Learn about the application of Maxwell's equations in cylindrical geometries.
  • Explore numerical methods for solving electromagnetic problems in complex geometries.
USEFUL FOR

Electrical engineers, physicists, and students studying electromagnetism, particularly those interested in power dissipation in dielectric materials and cylindrical geometries.

nutan123
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Homework Statement



A cylindrical cavity oriented along z axis with length of 2 m has a filament in it upon which a current of 10 A is impressed. Cavity is perfectly conducting whereas it is filled with lossy dielectric. Electric field on the cavity is given as: E=-z(i+j). One has to calculate the power dissipated in the cavity. BTW, the frequency is 5 kHz.

Homework Equations



[tex]\nabla[/tex][tex]\times[/tex][tex]\vec{E}[/tex]=-del(B)/del(t)
[tex]\nabla[/tex][tex]\times[/tex][tex]\vec{H}[/tex]=del(D)/del(t)+J
S=\vec{E}[/tex]\times[/tex][tex]\vec{H}[/tex]

The Attempt at a Solution



It has to do with the Poynting vector. I tried to find the mangetic field from the current but without any value for the permeability and permittivity for the lossy material how can I find the power loss. Is the fact that question provides the electric field is in some way helpful.
 
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nutan123 said:
A cylindrical cavity oriented along z axis with length of 2 m has a filament in it upon which a current of 10 A is impressed. Cavity is perfectly conducting whereas it is filled with lossy dielectric.

I assume you mean that the wall of the cavity is perfectly conducting while the cavity itself is filled with a dielectric?

Electric field on the cavity is given as: E=-z(i+j). One has to calculate the power dissipated in the cavity. BTW, the frequency is 5 kHz.


Is [itex]\textbf{E}=-z(\textbf{i}+\textbf{j})[/itex] the field on the cavity's wall, or throughout the cavity's interior?
 

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