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Hey guys, so I have a homework question that I have already solved one way, but when I try it another way I can't seem to get the correct answer.

First of all, the question is:

"A single resistor is wired to a battery as shown in the diagram http://session.masteringphysics.com/problemAsset/1011457/10/1011457A.jpg" [Broken] Define the total power dissipated by this circuit as P_0.

Now, a second identical resistor is wired in series with the first resistor as shown in the second diagram http://session.masteringphysics.com/problemAsset/1011457/10/1011457B.jpg" [Broken].

What is the power, in terms of P_0, dissipated by this circuit?"

Relevant equations:

P = V^2/R = I^2*R

So I have solved the equation by using V^2/R (P = V^2/(2R) = P_0/2), however the first way I tried to solve it was with I^2*R. I know this equation is correct, so why doesn't it give me the right solution? If anyone could give me an explanation I would be grateful. (My work is shown below)

P = I^2 * (R + R) = I^2 * 2R = 2 * P_0 ?

First of all, the question is:

"A single resistor is wired to a battery as shown in the diagram http://session.masteringphysics.com/problemAsset/1011457/10/1011457A.jpg" [Broken] Define the total power dissipated by this circuit as P_0.

Now, a second identical resistor is wired in series with the first resistor as shown in the second diagram http://session.masteringphysics.com/problemAsset/1011457/10/1011457B.jpg" [Broken].

What is the power, in terms of P_0, dissipated by this circuit?"

Relevant equations:

P = V^2/R = I^2*R

So I have solved the equation by using V^2/R (P = V^2/(2R) = P_0/2), however the first way I tried to solve it was with I^2*R. I know this equation is correct, so why doesn't it give me the right solution? If anyone could give me an explanation I would be grateful. (My work is shown below)

P = I^2 * (R + R) = I^2 * 2R = 2 * P_0 ?

## Homework Statement

## Homework Equations

## The Attempt at a Solution

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