Power of a sine wave (electronics engineering)

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Discussion Overview

The discussion revolves around the calculation of power for a sine wave in electronics, specifically the formula Power (Sine Wave) = 1/2 * (peak amplitude)^2. Participants explore the origins of this formula, its assumptions, and its application in communication systems.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the derivation of the power formula, seeking clarity on how power can be calculated from voltage without considering current or resistance.
  • Another participant suggests that the formula assumes a resistance of 1 Ohm, which is a common practice in power calculations.
  • Some participants mention the Poynting vector as a potential source for understanding the formula, although the connection remains unclear.
  • There is a reference to the Fourier Transform and its relevance to the discussion, but the relationship is debated and not fully established.
  • One participant emphasizes that the formula is an arbitrary convention based on the definition of instantaneous power through a 1 Ohm resistor.

Areas of Agreement / Disagreement

Participants express differing views on the assumptions underlying the power formula, particularly regarding the resistance value and the relevance of Fourier Transforms. The discussion does not reach a consensus on these points.

Contextual Notes

Participants note that the formula's application may depend on specific assumptions, such as the normalization to a 1 Ohm resistor, and that there are unresolved connections to concepts like the Fourier Transform and the Poynting vector.

priscared
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This is obviously an electronics question.
In communication systems, to calculate the power of a sine wave, the formula below is used
Power (Sine Wave) = 1/2 * (peak amplitude)^2

This formula is apparently a standard electronics formula.
I'm trying to understand where it comes from. How is it possible to get a power figure from a voltage only? There is no information on period, current, or resistance. Can some one please help explain the logic behind this formula for me?

Maybe its a simple trick, to me they've probably simply integrated the sign wave, but the limits must cancel out... i Don't know... help please..

Cheers
(
 
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priscared, I'm pretty sure the definition makes the assumption of "1" unit of resistance - where the unit is whatever makes sense to produce the power units you choose. I've asked this question several times, and that is the only answer I've seen.
 
yeah... normalised with a 1 Ohm resistor.
 
>> I'm trying to understand where it comes from.

It is derived from the http://en.wikipedia.org/wiki/Poynting_vector" .

>> How is it possible to get a power figure from a voltage only?

P = UI = U*(U/R) = U2/R
 
Last edited by a moderator:
Have you ever tried Fourier Transform of a pure sine?
 
what does that have to do with anything trambolin? I mean I know rayleighs equality... but we are wondering about the units here, right?
 
I meant power of a infinite signal in terms of 2-norm, Plancherel, parseval etc. If everything is normalized as you did for 1 ohm resistance... but anyway, nevermind, maybe you are right.
 
hmmm... indeed the poynting vector may have some relevance. But if some1 could point me to a meaningful explanation i would be impressed. I am assuming the assumptions is resistance = 1. And that's how the formula exists.

The rule almost seems like an anomaly, every1 uses it without thinking about its origin...
 
  • #10
" A signal's instantaneous power is
defined to be its square, as if it were a voltage or current passing through a 1 Ω resistor. "

THanks for the link

This rule is obviously just an arbitrary convention. It's obviously the definition of "instantaneous power".

BTw i can't see how this has anything to do with Fourier transforms.
 

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