Power Plant Efficiency & Heat Dissipation Calculations

Click For Summary
SUMMARY

The discussion focuses on calculating heat dissipation and flow rate requirements for a power plant generating 400 MW of electric power with an efficiency of 40%. The waste heat is determined to be 600 MW, calculated using the formula Pth - Pel. To maintain a maximum temperature rise of 3°C in the river, the flow rate is derived from the equation Pwaste = (ρ*V*c*ΔT)/t, where specific heat and density of water are essential parameters. The calculations presented are confirmed to be correct, assuming all wasted energy is lost as heat.

PREREQUISITES
  • Understanding of thermodynamic efficiency and power generation
  • Familiarity with heat transfer principles and specific heat capacity
  • Knowledge of fluid dynamics, particularly flow rate calculations
  • Basic proficiency in algebraic manipulation of equations
NEXT STEPS
  • Research "Thermodynamic efficiency in power plants" for deeper insights
  • Study "Heat transfer calculations in fluid systems" to enhance understanding
  • Explore "Specific heat of water and its implications in thermal systems"
  • Learn about "Fluid dynamics and flow rate equations" for practical applications
USEFUL FOR

Engineers, energy analysts, and students in mechanical or environmental engineering fields who are involved in power generation and thermal management.

Martinii
Messages
2
Reaction score
0
[SOLVED] Power plant

Hi! Here i have a problem : A power plant generates 400 MW of electric power.It has an effieciency of 40%.
a) At what rate does it dissipate heat?
b)If the waste heat is carried away by a river, and the temperature rise of the river must not exceed 3°C, what flow rate is required in the river?


Here is what i have tried:

a)
Pel=400 MW
η=40%=0.4
Pth=Pel/η=1000 MW

b) Pwaste=W/t Q=W=m*c*ΔT m=ρ*V

Pwaste=(ρ*V*c*ΔT)/t V/t= Volume Flow = V°= Pwaste/(ρ*c*ΔT)

Pwaste= Pth-Pel=600 MW and then calculations

I am not quite sure whether this way is correct or not.I will be happy if someone can tell me his opinion.
 
Physics news on Phys.org
Seems right to me, although there is at least one assumpution which is implied:
1. All of the wasted energy is lost as heat.
Fairly reasonable, there's bound to be some light and sound etc. but the vast majority will definitely be heat.

I don't fully understand your notation for Pwaste, but it looks pretty good. I guess one assumes that the river isn't below 0 C, and you can look up the specific heat of water, so that's no biggy. Seems like you got it.
 
Yeah , i think i got it! Thanks anyway :)
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
4K
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 15 ·
Replies
15
Views
3K