Power Series of Logs: Solving f(x)=x2ln(1-x)

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SUMMARY

The discussion focuses on finding the power series for the function f(x) = x²ln(1-x). A user initially attempted a Taylor series expansion, which proved to be time-consuming. Another participant suggested a more efficient approach by first determining the series for ln(1-x) and then multiplying the result by x². This method simplifies the process of obtaining the power series for the given function.

PREREQUISITES
  • Understanding of power series and Taylor series expansions
  • Familiarity with logarithmic functions, specifically ln(1-x)
  • Basic knowledge of calculus, particularly series manipulation
  • Experience with mathematical notation and function analysis
NEXT STEPS
  • Study the derivation of the power series for ln(1-x)
  • Practice multiplying power series to find new series
  • Explore the convergence of power series in different contexts
  • Learn about the applications of power series in solving differential equations
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus and series analysis, as well as anyone looking to streamline their approach to power series expansions.

jkim91@vt.edu
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First post! I'm having a lot of trouble with power series, especially when there's more than one of the same variable in a function.

Find the first few terms of the power series for the function
f(x)=x2ln(1-x)



I did a taylor series expansion of it, which gave me the right answer, but the work took forever. I figure power series would be a lot easier.
 
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I'm not too sure what you're asking? a taylor series is a power series around x=0

one way that could be quicker here though, is to find the series for ln(1-x) then multiply it by x^2
 

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