Power series question involving classical mechanics

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SUMMARY

The discussion focuses on calculating the force required to hold a weight in equilibrium when displaced by a force F, using classical mechanics principles. The key equations are TcosX = W and TsinX = F, where the goal is to express F/W as a power series of the angle X. The solution involves rewriting cosX in terms of the displacement x and the length of the string l, leading to the expression F/W = x/(l-x)(l+x)^(0.5). This approach simplifies the problem by focusing on the ratio x/l.

PREREQUISITES
  • Understanding of classical mechanics principles, specifically tension and equilibrium.
  • Familiarity with trigonometric functions and their series expansions.
  • Knowledge of Taylor series and its application in approximating functions.
  • Basic algebraic manipulation skills to rewrite equations.
NEXT STEPS
  • Study the derivation of Taylor series for trigonometric functions, particularly sinX and cosX.
  • Learn about the application of power series in solving mechanics problems.
  • Explore the concept of equilibrium in classical mechanics, focusing on forces and tensions.
  • Investigate the relationship between angular displacement and linear displacement in pendulum systems.
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Students and educators in physics, particularly those studying classical mechanics, as well as anyone interested in applying mathematical series to solve real-world problems involving forces and equilibrium.

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Homework Statement


A heavy weight is suspended by a cable and pulled to one side by a force F. How much force is required to hold the weight in equilibrium at a given distance x to one side.
From classical mechanics, TcosX= W and TsinX=F. Find F/W as a power series of X(angle).

Often in a problem like this, what we know is not X, but x(displacement) and l(length of string).

Find F/W as a series of powers in x/l


Homework Equations



TcosX=W
TsinX=F

The Attempt at a Solution



How do I calculate the power series for tanX? I've searched online but the people at yahoo answers got it wrong
http://en.wikipedia.org/wiki/Taylor_series
Wikipedia gives the answer but no route to it.

SinX= x/l

cosX= ((l-x)(l+x))^0.5/l

F/W = x/(l-x)(l+x)^0.5?
 
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You want things in terms of x/l. The sine already is, but the cosine isn't. Rewrite it slightly, like this

\cos X = \frac{\sqrt{l^2-x^2}}{l}} = \sqrt{1-\left(\frac{x}{l}\right)^2}

and go from there.
 

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