The discussion revolves around the power supplied by capacitors and inductors in AC circuits, specifically addressing the apparent contradiction between calculated reactive power and textbook assertions regarding average power being zero.
Some participants have provided insights into the nature of energy transfer in capacitors, noting that over a complete cycle, the net energy is zero. There is ongoing exploration of the power factor and its calculation, with no explicit consensus reached on the implications for the problem at hand.
Participants are discussing the assumptions related to ideal components, particularly the value of resistance in an ideal capacitor, which is suggested to be zero. There is also mention of differing conventions for power flow in the context of the problem.
Also, P is used for "real" power (which is 0 in this case), and Q is used for "reactive" power (which you calculated).engnrshyckh said:PQ=179VAR
How to find power factor in this case as P. F=COS@=R/ZTSny said:When AC voltage is applied to an ideal capacitor, the capacitor takes in energy for part of a cycle of voltage and the capacitor delivers energy back to the circuit for the remaining part of the cycle. The net energy delivered to the capacitor in one complete cycle is zero. So, over many cycles, there is no net energy supplied to the capacitor.
From the point of view of formulas, the average power supplied is not ##P_{\rm avg} = \large \frac{V^2}{Z}##. The formula should contain an additional factor called the "power factor". Is this something you have covered?
It should be zero if i am not wrong and cos0 becomes 1 so P. F of pure capacitive circuit become unityTSny said:For an ideal capacitor, what is the value of R?
Yes, R = 0.engnrshyckh said:It should be zero if i am not wrong
No, the formula says ##\cos \theta = R/Z##.and cos0 becomes 1