Power, Work, Kinetic Energy Problem

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Homework Help Overview

The problem involves a particle of mass 4.60 kg moving along the x-axis, with its position described by the equation x = t + 1.8t³. The questions focus on calculating kinetic energy, acceleration, force, power, and work done over a specified time interval.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the differentiation of the position function to find velocity and acceleration. There is mention of using kinetic energy formulas and the work-energy theorem. Some express confusion about the initial conditions needed for certain calculations.

Discussion Status

Participants are exploring various approaches to the problem, with some providing insights into the relationships between power, work, and kinetic energy. There is acknowledgment of the need for initial conditions, and some participants appear to be gaining clarity on the connections between the concepts involved.

Contextual Notes

There is a noted emphasis on deriving expressions rather than numerical values, which may influence how participants approach the problem. Initial conditions for velocity at t=0 are also under discussion.

yb1013
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Homework Statement



A 4.60 kg particle moves along the x axis. Its position varies with time according to x = t + 1.8t3, where x is in meters and t is in seconds.

(a) Find the kinetic energy at any time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(b) Find the acceleration of the particle and the force acting on it at time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(c) Find the power being delivered to the particle at time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(d) Find the work done on the particle in the interval t = 0 to t = 2.00 s.


Homework Equations



Im pretty that equations arent normal variable equations arent used here because I am asked for expressions, not just a numerical value.

The Attempt at a Solution



I've tried to fiddle around a little bit, but I've basically just made a mess of wrong answers... can someone please help me out here. I am very confused even on where to start on this question.
 
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yb1013 said:

Homework Statement



A 4.60 kg particle moves along the x axis. Its position varies with time according to x = t + 1.8t3, where x is in meters and t is in seconds.

(a) Find the kinetic energy at any time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(b) Find the acceleration of the particle and the force acting on it at time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(c) Find the power being delivered to the particle at time t. (Accurately round any coefficient to exactly two decimal places. Use t as necessary.)

(d) Find the work done on the particle in the interval t = 0 to t = 2.00 s.


Homework Equations



I'm pretty that equations aren't normal variable equations aren't used here because I'm asked for expressions, not just a numerical value.

The Attempt at a Solution



I've tried to fiddle around a little bit, but I've basically just made a mess of wrong answers... can someone please help me out here. I'm very confused even on where to start on this question.

I'm going to guess that's x(t) = t + 1.8t3... Well it's velocity as a function of time is v(t) = 1 + 5.4t2 and acceleration is a(t) = 10.8t both by differentiation.

Thus kinetic energy is given by KE = .5mv2.

Acceleration is given by what is above (the double derivative of x(t). F = ma.

What does power mean? Work from that definition.

Try the work/kinetic energy theorem for the the last part but you need initial conditions (namely initial velocity).
 
hmmm, I understood your first two explanations, but still kinda puzzled about the last 2... can you use Power = W/t
 
The last two are tied together.

If you do P = W/t then you need to calculate work.

W = [tex]\Delta KE = KE_{final} - KE_{initial}[/tex]. But to find KE you need a velocity which for some reason I thought needed a given value for t=0 but it's just v(0) = 1+5.4t2 = 1 m/s.

Good?
 
ok i think i got it, thank you
 

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