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Practice problem with invertible matrices

  1. Dec 14, 2009 #1
    Simplify: (B[tex]^{-1}[/tex]A[tex]^{T}[/tex])[tex]^{-1}[/tex]B[tex]^{-1}[/tex](ABA)[tex]^{T}[/tex]((AB)[tex]^{T}[/tex])[tex]^{-1}[/tex]

    Is the answer 1?

    thx
     
  2. jcsd
  3. Dec 14, 2009 #2
    Yep,
    [tex] A^{-T}B \ \ B^{-1}\ \ A^TB^TA^T \ \ A^{-T}B^{-t} = I[/tex]
     
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