Practice problem with invertible matrices

  • #1
Simplify: (B[tex]^{-1}[/tex]A[tex]^{T}[/tex])[tex]^{-1}[/tex]B[tex]^{-1}[/tex](ABA)[tex]^{T}[/tex]((AB)[tex]^{T}[/tex])[tex]^{-1}[/tex]

Is the answer 1?

thx
 

Answers and Replies

  • #2
341
0
Yep,
[tex] A^{-T}B \ \ B^{-1}\ \ A^TB^TA^T \ \ A^{-T}B^{-t} = I[/tex]
 

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