Pressure, Density, and Atmospheric Pressure

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SUMMARY

The absolute pressure at a depth of 15 meters below the surface of the sea is calculated using the formula P = ρgh, where ρ is the density of seawater (1.03 g/cm³), g is the acceleration due to gravity (10 m/s²), and h is the depth (15 m). The pressure due to the seawater column is 153.5 kPa, which, when combined with the atmospheric pressure of 101 kPa, results in a total absolute pressure of 254.5 kPa. This calculation demonstrates the relationship between depth, density, and pressure in fluid mechanics.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Knowledge of pressure calculations in physics
  • Familiarity with the concept of density
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the hydrostatic pressure equation in detail
  • Learn about the effects of varying fluid densities on pressure calculations
  • Explore applications of pressure calculations in engineering contexts
  • Investigate the relationship between depth and pressure in different fluids
USEFUL FOR

Students studying physics, engineers working with fluid systems, and anyone interested in understanding the principles of pressure in liquids.

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Homework Statement



What is the absolute (total) pressure at the depth of 15 m below the surface of the sea. Assume density of seawater is 1.03 g/cm3 and g=10 m/s2. Give answer in kPa. Use atmospheric pressure is 101 kPa.


Homework Equations



P = F/A
P1V1=P2V2


The Attempt at a Solution



i don't know how to solve it because neither of the formulae my teacher gave me have atmostpheric pressure or density and the problem doesn't have volume please help!
 
Physics news on Phys.org
Pressure in this case doesn't depend on volume, it just depends on gravity, density and the height of the fluid column above you. You've probably seen the equation before- p=d*g*h.

The total, then, is just that plus atmospheric pressure.
 

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