Pressure drop across orifice , calculation help

Click For Summary
The discussion focuses on calculating the pressure drop across an orifice plate and the mass flow rate of a fluid flowing through a pipe. The fluid has a relative density of 0.86 and viscosity of 0.003 Pa, with a flow rate measured using a 6cm diameter orifice. The pressure drop was calculated using the difference in mercury levels in a manometer, yielding a value of 12485.2 Pa, but the expected answer is 125000 Pa. The volumetric flow rate and mass flow rate calculations also show discrepancies, with the user obtaining 8.17 kg/s instead of the expected 8.39 kg/s. Assistance is sought to identify the errors in these calculations.
tweety1234
Messages
111
Reaction score
0

Homework Statement



A fluid of relative density 0.86 and viscosity 0.003 pa flows through a pipe of 12cm diameter. The flow rate is measured using an orifice plate with a 6cm diameter orifice, with pressure tapping connected to a differential U-tube manometer using mercury (density = 13600 kg m^{-3} ) as the manometer fluid. The coefficient of discharge of the orifice meter is 0.62. The difference in mercury levels in the manometer is 100mm. Calculate the pressure drop across the orifice plate and the mass flow rate of the fluid. Then calculate the Reynolds number Number based on the orifice diameter.

equations needed ;

\bigtriangleup P = (\rho_{F} - \rho) g \bigtriangleup h

Q = \displaystyle C_{D} A_{0} \sqrt{\frac{2(p_{1}-p_{2})}{\rho (1-\frac{A_{0}}{A_{1}}^{2})}

Re = \frac{4M}{\pi D \mu}

mass flow rate Q \rho = m

A_{0} = 0.01131 m^{2}

A_{1} = 2.827 m^{2}

pressure drop = \bigtriangleup P = (\rho_{F} - \rho) g \bigtriangleup h

= (13600-860)9.8 x 0.1 = 12485.2 pa

The correct answer is 125000, I think they may have rounded up ?

2) Volumetric flow rate = (0.62)(0.01131) \sqrt{\frac{(2\times12485.2)}{13600 ( 1-\frac{0.01131}{2.827}^{2})} = 9.50 \times 10^{-3}

mass flow rate = (9.50 \times 10^{-3}) \times 860 = 8.17the correct answer is 8.39 kg s^{-1}

I can't see where I am going wrong, and help appreciated.
 
Physics news on Phys.org
Anyone know?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
5
Views
3K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
4K
  • · Replies 23 ·
Replies
23
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
16K
Replies
1
Views
2K