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Pressure due to uneven water distribution in connecting pipe

  1. Mar 12, 2016 #1
    1. The problem statement, all variables and given/known data
    WrCJqe2.jpg

    2. Relevant equations
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    3. The attempt at a solution
    Im confused by this question, just looking at the diagram without any maths you can see what would happen. C and D would want to reach equilibrium and be at the same level so the pressure down on D would be the difference in heights of the fluid. ie. 12 h times p g. but the equation says 15 not sure how they arrived at that? could anyone here help please? i am trying to get the formula given
     
  2. jcsd
  3. Mar 12, 2016 #2

    TSny

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    The 15h in the answer relates the pressure at D to atmospheric pressure. You are right that the pressure at D is related to the pressure at C by 12h.
     
  4. Mar 13, 2016 #3
    Many thanks for the reply! ok so the pressure at D, is the atmospheric pressure minus (because it acts in the opposite direction) the pressure due to unequilibrium? I still cant see where the 15 comes from, please could you expand a little? thanks again
     
  5. Mar 13, 2016 #4

    TSny

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    See if you can work your way through the system point by point. Find P at A, then B, then C, then D. (You can probably skip A.)
     
  6. Mar 13, 2016 #5
    ok will try that, thanks again!
     
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