Pressure in a container placed on a reduced area?

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SUMMARY

The discussion clarifies that within a closed container with a uniform pressure of 1 Pascal, the pressure remains constant regardless of the area measured. The pressure exerted on a smaller area, such as 1 mm², does not increase to 1000 Pascals; it remains at 1 Pascal. The force can be calculated using the formula F = P * A, where P is the pressure and A is the area. Thus, while the force on a smaller area may be less intuitive, the pressure itself does not change.

PREREQUISITES
  • Understanding of basic physics concepts such as pressure and force.
  • Familiarity with the formula P = F / A.
  • Knowledge of units of measurement, specifically Pascals and square meters.
  • Basic comprehension of gas behavior in closed systems.
NEXT STEPS
  • Research the principles of fluid mechanics and pressure distribution in closed systems.
  • Study the applications of the formula F = P * A in various engineering contexts.
  • Explore the behavior of gases under different pressure conditions using simulations.
  • Learn about the implications of pressure changes in real-world scenarios, such as in pneumatic systems.
USEFUL FOR

Students of physics, engineers working with fluid dynamics, and anyone interested in understanding pressure behavior in closed systems will benefit from this discussion.

randombill
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Really simple question but it's been making me a little confused.

Lets imagine we have a container (cubic with length of 1 meter) with a pressure of 1 Pascal and then an area inside the container of 1 mm^2 is chosen to measure the force on that area, what would the pressure be? 1 Pascal or 1000 Pascals?

My guess is the gas pressure applied to the smaller area would be larger than the pressure on the walls of the entire container similar to how a hammer can put a nail in wood easier than a blunt object.
 
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If the container is closed and has an internal pressure of 1 pascal, then the pressure everywhere inside the container is the same: 1 pascal.

Now, the equivalent force over a certain area in the container will change, since the pressure P = F / A. P is a constant, but A can be chosen as 1 cm2, or 1 mm2 or whatever, and F can be calculated by F = P * A.
 
SteamKing said:
F can be calculated by F = P * A.
Thanks! now it makes sense.
 

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