Pressure in a Tank: Questions & Answers

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SUMMARY

The discussion focuses on calculating the pressure at the bottom of a tank on an oil tanker during filling operations. Given a tank depth of 20 meters and an inert gas blanket pressure of 400 mm water gauge, the pressure at the valve when a pressure gauge reads 1 Bar is determined by the hydrostatic pressure equation, P_liq = h * d * g. When the tank is filled to a height of 15 meters, the pressure can be calculated using the same principles, leading to a final pressure that accounts for both the liquid and gas pressures in the tank.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with gas laws, specifically PV=nRT
  • Knowledge of pressure measurement units, including Bar and mm water gauge
  • Basic concepts of fluid dynamics in closed systems
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  • Research hydrostatic pressure calculations in fluid mechanics
  • Learn about the implications of gas laws in confined spaces
  • Explore pressure measurement techniques and conversions
  • Study the effects of liquid density on pressure in tanks
USEFUL FOR

Marine engineers, oil and gas industry professionals, and anyone involved in tank operations and fluid dynamics will benefit from this discussion.

rachit mehra
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Hi all, this will seem a very easy problem for you guys but its really a bit conufusing for me..
I work on an oil tanker and the problem is as follows.
What will be the pressure on the filling line of a tank which is on deck when oil is being filled into the tank. For sake op simplicity let's take the density as 1.0. The tank is 20 metres deep and the valves are at bottom.( The entry point is on the top, and the oil flows down to the bottom of the tank and enters the tank at the bottom) . The tank has an inert gas blanket wih a pressure of about 400 mm water gauge.
Now my questions are-
1) What will be the pressure on the bottom line at the valve when a pressure gauge shows a pressure of 1 Bar.
2) If the tank is filled up to a height of 15 metres what will be the pressure then .

Thanks
 
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I suppose there will be a gas with oil too. Is it? Let's choose two points in tank. One is in liquid(A) and other is not(B).

Total pressures,

PA = Pgas + P liq
PB = Pgas

P liq = h d g

Also, if gas can not get out, even filling the tank, gas pressure will grow. If this is an ideal gas then,

PV=nRT

and n, R, T is not changing when filling. Thus,

PV= const.

Say, the gas has P pressure in tank and volume is V then, half of tank filled with liquid. Now,

PV = Pf*V/2 (Pf: Final pressure)
Pf=2P

hope this helps. (If i could understand properly)
 

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