Pressure increase required for 1 Joule of work

[Bergman]

Homework Statement

Estimate the pressure increase required to impart one joule of mechanical work in reversibly compressing 1 mol of silver at room temperature.
Same process for alumina.

Homework Equations

W=-PdV
dV=V(alpha)dT-V(beta)dP
dT=0

The Attempt at a Solution

I used the work equation and the equation for dV to find the following:

delta W=-P[-V(beta)dP]
delta W= V(beta) integral (PdP)
W= VBeta/2 * (P2^2-P1^2) When I try to use this equation with the values in my textbook, I am not getting the correct answer. My book gives the molar volume as 10.27 cc/mol, and the beta value for silver as 9e7.
At this point I'm not entirely sure if my equation is correct and I'm simply making a mistake in my calculations or units, or I'm very far off. Any advice would be greatly appreciated.

 

[mfb]

When I try to use this equation with the values in my textbook, I am not getting the correct answer.

It would help if you could say what you get and what the book gets.

 

[Bergman]

I have continued working on the problem, and found the relationship 1J=9.8699 cc atm. When I use this I get:

2* 9.8699 cc atm / (10.27 cc * 9e-7) = P2^2-P1^2

In which case I get 1461.4 atm

The book gave the compressibility as 9 e7, but I think it should be 9 e-7

The answer in the back of the textbook is 9 e6 atm

 

[mfb]

Neglecting atmospheric pressure:
This page quotes 0.00993 GPa^-1 for silver and confirms the molar volume.

At 1461*10⁵ Pa, we compress it by 0.00145, and I get 1.09 J, that fits.

At 9 million times the atmospheric pressure (?) silver doesn't behave linearly any more.

 

[Bergman]

Thank you for the help, I really appreciate it. I may contact my professor to ask if the textbook may be wrong, considering that I have been able to do the same calculation for alumina, and get the expected value.