(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Estimate the pressure increase required to impart 1 J of mechanical work in reversibly compressing 1 mol of silver at room temperature. What pressure rise would be required to impart 1 J of work to 1 mol of alumina at room temperature? For alumina take the molar volume to be 25.715 (cc/mol) and (BETA)=8*10^(-7) (atm)^(-1).

For silver, the molar volume is 10.27 (cc/mol) and (BETA)= 9.93*10^(-6)

Beta is the coefficient of compressibility

2. Relevant equations

Mechanical Work= -PdV

dV=V(ALPHA)dt-V(BETA)dP

3. The attempt at a solution

I assumed that temperature remained constant during this process. I know that the answer should be 9.6*(10)^6 atm for silver and 978 atm for alumina. I have been getting 140041 atm for silver and 311800 atm for alumina. The attempt is attached below. Any ideas as to what I'm doing wrong? Thanks in advance!

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# Homework Help: Thermodynamics: Calculating Pressure Increase From Work

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