Water at standard atmospheric pressure and temperature fills a sealed, rigid container. If the temperature of the water is increased by 50°C, what is the pressure? V = volume, P = pressure, T = temperature Coefficient of compressibility, kappa = (-1/V)(dV/dP) Coefficient of thermal expansion, beta = (1/V)(dV/dT) I solved for dV/V from the coefficient of thermal expansion equation: dV/V = beta*dT. Plugging into coefficient of compressibility equation: kappa = -(beta*dT)/dP. Solved for dP = -(beta*dT)/kappa, changed the d's into deltas. Plugging kappa = 5.18 * 10^-10 and beta = 1.48 * 10^-4 into delta P equation gave me delta P = -92.3 MPa. Is this reasonable at all? I mean, the pressure difference seems a bit large.