Pressure of gas when temperature and volume increases

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Homework Help Overview

The discussion revolves around the behavior of gas in a syringe as it is heated from 20 degrees to 100 degrees. Participants explore how various quantities, such as average distance, pressure, average speed of gas, and frequency of collisions with the piston, change with temperature while maintaining the same pressure as the surrounding air.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question why the frequency of collisions remains the same despite an increase in average speed of gas molecules at higher temperatures. They discuss the implications of the cylinder's length increasing and how it affects the time between collisions.

Discussion Status

There is an ongoing exploration of the relationship between temperature, speed, and collision frequency. Some participants express skepticism about the correctness of the official answer key, suggesting that their reasoning may be valid.

Contextual Notes

Participants are navigating the complexities of gas behavior under changing conditions, with specific attention to the assumptions made in the problem statement and the potential discrepancies in provided answers.

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Homework Statement


A syringe contains gas at the same pressure as the air outside. The piston moves freely along the cylinder without any friction. No gas escapes. As the syringe is heated from 20 degrees to 100 degrees the piston moves outwards. It stops moving when the temperature is steady. State how the value of each of the following quantities compares at 100 degrees, after the piston stops with its value at 20 degrees.
average distance - increased
pressure after it stops - same
average speed of gas - increased
frequency of collisions of the gas on the piston - same


Homework Equations



none

The Attempt at a Solution


i don't understand why the frequency of collision of the gas on the piston remains the same. Since at 100 degrees the pressure is the same as it was previously so shouldn't the frequency of collision be the smaller as average speed of gas increases, in order for the pressure to remain the same the frequency of collision must be smaller?

thanks for the help!
 
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Think: The length of the cylinder increases so the molecules need longer time to get back to the piston.

ehild
 
ehild said:
Think: The length of the cylinder increases so the molecules need longer time to get back to the piston.

ehild

but the formula is Force on the wall = frequency * impulse of collision so if impulse increase won't frequency decrease?
 
You are right, the average force is impulse of the collision multiplied by the collision frequency. The pressure is the same, so the average force is the same, but the speed of the molecules is greater at higher temperature, the impulse is greater, so the frequency decreases.
Also, the length of the cylinder increases with the temperature, the speed of the molecules also increases, but the length is proportional to the temperature T and the speed is proportional to the square root of T, so the time between two collisions increases, the frequency decreases.

ehild
 
ehild said:
You are right, the average force is impulse of the collision multiplied by the collision frequency. The pressure is the same, so the average force is the same, but the speed of the molecules is greater at higher temperature, the impulse is greater, so the frequency decreases.
Also, the length of the cylinder increases with the temperature, the speed of the molecules also increases, but the length is proportional to the temperature T and the speed is proportional to the square root of T, so the time between two collisions increases, the frequency decreases.

ehild

But why did the answer key from O levels put it as same? Are they wrong?
 
It happens quite frequently that the "official" answers are wrong. I hope that is the case now, and we are right. :smile:

ehild
 
ehild said:
It happens quite frequently that the "official" answers are wrong. I hope that is the case now, and we are right. :smile:

ehild

ok thanks for the help! i hope we are right too :smile:
 

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