Pressure on uniformly charge spherical shell

Click For Summary
SUMMARY

The discussion centers on calculating the pressure exerted on a uniformly charged spherical shell with charge Q and radius R. The electric field inside the shell is zero (E = 0 for rR. The pressure on the shell is derived using the principle of virtual work, leading to the formula pressure = Q²/(32*Pi²*eps*R²). A correction was noted regarding a missing factor of R² in the denominator, confirming the final pressure equation is accurate as stated.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with the principle of virtual work in physics
  • Knowledge of spherical coordinates for integration
  • Grasp of energy stored in electric fields
NEXT STEPS
  • Study Griffiths' "Introduction to Electrodynamics" for detailed explanations on electrostatic pressure
  • Learn about the principle of virtual work in classical mechanics
  • Explore advanced integration techniques in spherical coordinates
  • Investigate applications of electric field energy in various physical systems
USEFUL FOR

Students and professionals in physics, particularly those focusing on electrostatics, as well as educators seeking to clarify concepts related to electric fields and pressure in charged systems.

timhunderwood
Messages
11
Reaction score
0

Homework Statement



First part of the problem was to work out E-field of uniformly charged spherical shell with charge Q and Radius R.

This was fine : E = 0 for r<R
and E = Q/(4*Pi*eps*r2) for r>R

QUESTION:
Find the pressure exerted on the shell due to the charges on its surface.

Homework Equations


The Attempt at a Solution



I tried to do it using the principle of virtual work, I get an answer and was hoping someone could confirm it is right?

I did this:
u_s, Energy stored in Electric field = \inteps*E2/2 (integrate over all space)

I did this in spherical polar coordinates and get U_s = Q2/(8*Pi*eps*R)

I then said (principle of virtual work:)

F, Force*dR = \partialU_s/\partialR *dR
and solved this to get:
F = -Q2/(8*Pi*eps*R2)

dividing by area of shell then gives

pressure = Q2/(32*Pi2*eps*R2)

is this right? If there's a mistake I think I may have not used the principle of virtual work correctly...

Thanks very much.
 
Physics news on Phys.org
I do believe you are making this a little more complicated than necessary. The electrostatic pressure on the surface is given by the formula

P=\frac{\varepsilon_0}{2}E^2

(cf. Griffiths Equation 2.52)
 
timhunderwood said:
pressure = Q2/(32*Pi2*eps*R2)

is this right? If there's a mistake I think I may have not used the principle of virtual work correctly...
You're missing a factor of R^2 in the denominator, but otherwise, yes, that is fine.
 
Thats good,

I mistyped my last equation- it should have read R^4.

Thanks for the help
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
678
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
4
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
890
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K