Pretty Simple Probability Question

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The discussion revolves around calculating the probability of conception for a couple with a monthly conception probability of 1/8. The mean number of cycles until conception occurs is determined using the geometric distribution, yielding a mean of 8 cycles. Additionally, to find the smallest n such that the probability of taking more than n cycles is less than 1/2, the cumulative distribution function of the geometric distribution is applied, resulting in n = 3. The calculations involve understanding the probability mass function and expectation value.

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ChemIsHard
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The question is:

A couple is trying to get a child. Their probability of conception in any given monthly cycle
is 1/8
(a) What is the mean number of cycles until conception occurs (the count includes the cycle
in which conception occurs)? Neglect menopause and limited lifetime of the couple.
(b) What is the smallest n such that the probability that it takes them more than n cycles
is less than 1/2 ?

I attempted to use a binomial distribution but realized that took me no where...I know it should be somewhere within 3-5 months but I can't prove it.

I know this is simple, and that I'm likely over thinking.

Thanks in advance.
 
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It sounds like a binomial distribution to me.

Anyway, can you calculate what the probability P(n) is that conception takes place in the nth month? Because then you can simply calculate the expectation value of n through
E = \sum_{n = 0}^\infty n P(n)
 

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