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- Thread starter nidak
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- #2

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Given any primitive root, it follows that r^(p-1)==1 Mod p, **but not for any lesser power.** But (p-l)/3 =u, is an integer less than p-1, and it follows that:

(a^3)^u ==1 Mod p.

(a^3)^u ==1 Mod p.

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Look up Henzel's lemma in Lang or Milne's online course note. It is relavant.

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Look up Henzel's lemma in Lang or Milne's online course note. It is relavant.

No need to use Hensel's lemma, what robert did is perfect.

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