Prism Question: need this by tonight

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SUMMARY

The discussion revolves around calculating the deviation of a light ray passing through a prism with a +500D mirror and an incident angle of 30 degrees. The user is uncertain about how to proceed due to the absence of the prism's index of refraction and the alpha angle. The relevant equations include Snell's Law and the deviation formula, but without specific values, the user cannot determine the deviation accurately. The user speculates that the deviation might be 60 degrees, but this remains unverified due to missing parameters.

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Homework Statement



A light ray has an incident angle of 30 degrees onto the vertex of a +500D mirror in air (directly on the optical axis). By how many degrees is the light ray deviated from its original path?


Homework Equations



n (delta) = (n'-n) (alpha)

n'= [ n sin [(alpha + delta)/2] / [sin (alpha /2)]

alpha = i1' + i2

n sin i1 = n' sin i1'

n' sin i2 = n sin i2'

but the prism index is not given and the alpha angle is not given so I don't know how to approach this question.

The Attempt at a Solution



choices are:
a. 0 degree
b. 30 degrees
c. 60 degrees
d. 90 degrees
e. 120 degrees
 
Last edited:
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I think the answer is c. 60 degrees but I don't know how to solve it without the prism index and the alpha angle.
 

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