Probability Density: Battery Life Homework

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Homework Help Overview

The problem involves the probability distribution of battery life, specifically focusing on a normally distributed lifespan with a mean of 4 years and a standard deviation of 1.2 years. The questions pertain to calculating the probability of a battery lasting more than 6 years and determining an appropriate warranty period that would cover 95% of the batteries sold.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of the warranty period in relation to the 5% failure rate and question how to calculate the necessary time frame. Some suggest using cumulative distribution functions and Z-scores to find probabilities related to battery life.

Discussion Status

The discussion is active, with participants exploring different methods to approach the problem. Some have provided insights into using Z-tables and cumulative distribution to find relevant probabilities, while others are clarifying their understanding of the problem's requirements.

Contextual Notes

Participants express uncertainty regarding the interpretation of the 5% failure rate and how it relates to the warranty period. There is also mention of using specific tables and formulas to derive answers, indicating a reliance on external resources for calculations.

kukumaluboy
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Homework Statement



c. The life of a certain brand of battery is normally distributed with a mean of 4 years and a
standard deviation of 1. 2 years.
i. If a battery is selected at random, what is the probability that it will last for more than 6
years? (5 marks)
ii. How long a warranty period should the manufacturer provide if he is willing to replace
at most 5% of all the batteries sold? (5 marks)

Homework Equations





The Attempt at a Solution


Part (i) i can do. Part (ii) dun understand. 5% of all batteries sold? how many are they?
 
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so a single battery hsould have a 95% probability of lasting the warranty period
 
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So should we do (b - a) in years ?
 
i would look at the cumulative distribution & pick of the time at 5%

as your pdf is defined in years, I would find the answer in years
 
I tried working from the answer, the Z value have to be -1.65
 
ok so in that table you want to find when the probability is 0.45 (the othe side of the curve will give you 0.5 probabiliy as it is symmetric)

so reading off P = 0.45, at z=1.65

so 95% of the batteries will have a life greater than
= Mean - 1.65 x SD
= 4yrs - 1.65x1.2 = 4-2.3 = 1.7

which is pretty close to 2
 

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