Probability Estimation with NETICA: Help for Civil Engineering Student"

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The discussion focuses on estimating the probability that an employee who tests positive for narcotics is actually a user, using Bayes' theorem. The user calculates the probability as approximately 19.92% based on given test accuracy rates and the prevalence of drug use among employees. NETICA software is mentioned as a tool for Bayesian network analysis, but the user expresses difficulty in using it. Another participant confirms the calculation is correct but suggests using decimal notation for clarity. The conversation highlights the application of probability theory in decision-making scenarios relevant to civil engineering studies.
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Assume that a narcotics test gives positive results in 99% for drug users. For people not
using narcotics the test gives negative results in 98% of cases. A company decided to test its employees knowing that 0.5% of them use drugs. Estimate the probability that a person with a positive test result is indeed a user. Estimate using the NETICA software.

Hi, I'm studying Civil Engineering and now I have some humanity courses. For subject Decision Making and Negotiation Theory I have to do above problem. Can anyone know Netica and can help me? Thx.
 
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Dang! I don't even know what NETICA stands for, let alone know how to use it. Of course, I suppose you aren't allowed to just use Bayes rule...so easy...

Welcome to physics forums.
 
Well, the first task was to use Bayes formula and I did this like that:

P(U) = 0.5%
P(N) = 99.5%
P(CU|U) = 99.0%
P(CN|U) = 1.0%
P(CU|N) = 2.0%
P(CN|N) = 98.0%

P(U|CU) = [P(CU|U)*P(U)] / P(CU)
P(U|CU) = [P(CU|U)*P(U)] / [P(CU|U)*P(U) + P(CU|N)*P(N)]
P(U|CU) = [99% * 0.5%] / [99% * 0.5% +2.0% * 99.5%]
P(U|CU) = 19.92%

Is that correct?

Due to norsys.com website 'Netica, the world's most widely used Bayesian network development software, was designed to be simple, reliable, and high performing.' While for me isn't because I don't know how to use it.
 
Yes, your calculation is correct, although I would have expressed the algebra with decimals instead of percents. Remember, probabilities are numbers in the interval [0,1].
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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