Probability Final: Is (a) or (b) a Valid Random Variable?

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Homework Help Overview

The discussion revolves around the concept of valid random variables in probability theory, specifically examining two cases (a) and (b) to determine their validity based on the definitions and conditions provided.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of valid random variables, questioning the conditions under which a mapping from the sample space is considered valid. There is a focus on the implications of the null set and its relation to the conditions for both cases (a) and (b).

Discussion Status

The discussion is active, with participants offering insights into the validity of the conditions for both cases. Some have pointed out the vacuous nature of certain arguments, while others are probing deeper into the requirements for a random variable to be valid.

Contextual Notes

There appears to be some confusion regarding the implications of the null set in relation to the conditions for valid random variables, particularly in how it applies to the definitions provided in the problem statement.

Shackleford
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I'm reviewing the early stuff, and I'm a bit fuzzy on what is a valid random variable. I don't see why (b) is valid while (a) is not. For (b), it says the set is in the family of subsets for all x. There's no mapping from the sample space that is less than or equal to -5. Well, then I thought it might be the null set satisfies this. However, why doesn't the null for (a) satisfy X(s) ≤ 1?

http://i111.photobucket.com/albums/n149/camarolt4z28/Untitled-7.png?t=1304620770
 
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First of all, asking whether the null set satisfies some condition is vacuous.

{s in S | X(s) ≤ 1} = {1} which indeed is not in E.
 
Do you understand my question? Certainly, I see there is no mapping from the sample space that satisfies that. However, it has to be valid for all x to be a random variable. How does (b) satisfy that outside of the sample space mapping? For example, for {s in S | X(s) ≤ -5} = {?}
 
I understand the actual problem. Still not sure what you're misunderstanding.

In part b), {s in S | X(s) ≤ x} is the empty set for any x in (-infinity, -1), and the empty set is in E, so yes obviously {s in S | X(s) ≤ -5} = empty set, which is in E.

For part a), X(1) is less than OR EQUAL TO 1, so {s in S | X(s) ≤ 1} = {1}, which is NOT in E.
 

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