Calculate Probability of Losing 5, 10, 20 Times in a Row

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To calculate the probability of losing multiple times in a row with an 80% chance of winning and a 20% chance of losing, use the formula 0.2^k, where k represents the number of consecutive losses. For example, the probability of losing 5 times in a row is 0.2^5, which equals 0.00032 or 0.032%. Similarly, for 10 losses in a row, it is 0.2^10, and for 20 losses, it is 0.2^20. The discussion also touches on the maximum number of losses in a sequence over 500 occurrences, emphasizing the importance of understanding independent trials in probability calculations. Mastering this calculation allows for better predictions in scenarios involving repeated independent events.
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Probability help...

If i have a standard 80% chance of wining and 20% chance of losing
than what is the chance of me losing 5 times in a row 10 times in a row
and 20 times in a row.

I would be very grateful if someone can show me how to calculate this on my own.

Thanks

I am trying to figure out the maximum number of divination in the losing direction
so occurrences 500.
 
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Since your chance of losing is .2, the chances of losing k times in a row (assuming independence of the trials) is .2k.

Your last sentence has typos - I can't understand it.
 
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