Probability of failure question?

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SUMMARY

The discussion centers on calculating the probability of failure for a concrete specimen with a compressive strength that follows a normal distribution, characterized by a mean of 2.8 ksi and a coefficient of variation (COV) of 0.1. The applied stress is 2.5 ksi, and participants concluded that the probability of failure, calculated using MS Excel, is approximately 14.2%. The variance was determined to be 0.28 ksi, which is essential for understanding the distribution of compressive strength.

PREREQUISITES
  • Understanding of normal distribution and its properties
  • Familiarity with statistical concepts such as mean and variance
  • Proficiency in using MS Excel for statistical calculations
  • Knowledge of compressive strength testing in concrete materials
NEXT STEPS
  • Learn how to apply the normal distribution formula for probability calculations
  • Explore advanced statistical functions in MS Excel for engineering applications
  • Study the implications of coefficient of variation (COV) in material strength analysis
  • Investigate methods for determining maximum failure stress in concrete specimens
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Engineers, material scientists, and students in civil engineering or structural analysis who are involved in assessing the reliability and performance of concrete under stress conditions.

Xinio64
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Homework Statement


"The compressive strength of a concrete specimen follows a normal distribution with a mean value of 2.8 ksi and a coefficient of variation (COV) of 0.1. If the applied stress is 2.5 ksi, find the probability of failure."


Homework Equations


normal distribution formula


The Attempt at a Solution


I got the variance to be .28 ksi but i don't know how to find the probability of failure without knowing the maximum failure stress of the specimen. Can anyone help me out?
 
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Xinio64 said:

Homework Statement


"The compressive strength of a concrete specimen follows a normal distribution with a mean value of 2.8 ksi and a coefficient of variation (COV) of 0.1. If the applied stress is 2.5 ksi, find the probability of failure."


Homework Equations


normal distribution formula


The Attempt at a Solution


I got the variance to be .28 ksi but i don't know how to find the probability of failure without knowing the maximum failure stress of the specimen. Can anyone help me out?

Since the applied compressive stress is 2.5ksi you need to calculate the probability that the compressive strength will be below this value. From MS Excel I estimate this should be 14.2%.
 

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