Probability of Thyroid Deficiency in Randomly Chosen Group of 12 Persons

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SUMMARY

The probability of at least one person having a thyroid deficiency in a randomly chosen group of 12 individuals from a town where 10% have the deficiency is calculated as 1 minus the probability that none of them have the deficiency. The correct probability is 0.7176. This approach simplifies the calculation by focusing on the complementary probability rather than summing multiple combinations of individuals with the deficiency.

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Medical records show that one out of 10 persons in a certain town has a thyroid deficiency. If 12 persons in this town are randomly chosen and tested, what is the probability that atleast one of them will have a thyroid deficiency.

I know atleast 1 means 1 or 2 or 3 or 4 and so on up to 12. So we just sum all the terms once we get them.

But i am a bit confused on what to do.

Should it be .10( 12!/1!11! + 12!/2!10! + ... + 12!/10!2! + 12!/11!1! + 12!/12!)?

I do not think that is right. can someone explain to me what to do.

The correct answer is .7176
 
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There is more than one way to approach this problem, but I think the easiest way is to observe that the probability that at least one person has the disease is 1 minus the probability that none of the 12 have the disease.
 

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