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Homework Statement
In a lab experiment, a mouse can choose one of two food types each day, type I and type II. Records show that if a mouse chooses type I on a given day, then there is a 75% chance that it will choose type I the next day and if it chooses type II on one day, then there is a 50% chance that it will choose type II the next day.
(a) If the mouse chooses type I today, what is the probability that it will choose type I two days from now?
(b) If the mouse chooses type II today, what is the probability that it will choose type II three days from now?
Homework Equations
The Attempt at a Solution
I think a suitable transition matrix for this phenomenon is:
[tex]Px_{t} = \left[\begin{array}{ccccc} 0.25&0.5 \\ 0.75&0.5 \end{array}\right][/tex] [tex]\left[\begin{array}{ccccc} x_{1}(t) \\ x_{2}(t) \end{array}\right][/tex]
for part (a) I have the initial condition [tex]\left[\begin{array}{ccccc} 1 \\ 0 \end{array}\right][/tex]
[tex]\left[\begin{array}{ccccc} 0.25&0.5 \\ 0.75&0.5 \end{array}\right][/tex] [tex]\left[\begin{array}{ccccc} 2 \\ 0 \end{array}\right][/tex][tex]= \left[\begin{array}{ccccc} 0.5 \\ 1.5 \end{array}\right][/tex]
So the probability is 0.5?
for part (b) the initial condition is (0,1). This time we end up with:
[tex]= \left[\begin{array}{ccccc} 1.5 \\ 2.5 \end{array}\right][/tex] !
The probability of choosing type II in three days is 2.5