Probability Question experiment

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The discussion revolves around the probabilities of two events, A and B, derived from five possible outcomes. It explores whether various probability relations can hold true, providing numerical examples for those that can. For instance, P(A) can equal P(B) and P(A) can equal 2P(B) under certain distributions. However, the relation P(A) - P(B) > 1 cannot hold, as both probabilities must be between 0 and 1. The analysis emphasizes the importance of understanding probability distributions in determining the validity of these relations.
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Homework Statement


Suppose that an experiment has five possible outcomes, which are denoted {1,2,3,4,5}. Let A be the Event {1,2,3} and let B be the event {3,4,5}. (Notice that we did not say that the five outcomes are equally likely: The probability distributions could be anything.) For each of the following relations, tell whether it could possibly hold.

If it could, give a numerical example using a probability distribution of your own choice; if it could not, explain why not (what rule is violated).

a. P(A) = P(B)
b. P(A) = 2P(B)
c. P(A) = 1 - P(B)
d. P(A) + P(B) > 1
e. P(A) - P(B) < 0
f. P(A) - P(B) > 1

Homework Equations


The Attempt at a Solution

I am honestly not sure If I am doing these right, so please correct me if I am in the wrong direction.

a. P(A) = P(B)
Can Hold: Example if set is uniformly distributed.
P(A) = .6 = P(B)

b. P(A) = 2P(B)
Can hold:
P(1)=.35
P(2)=.3
P(3)=.05
P(4)=.15
P(5)=.15

.7 = .7

c. P(A) = 1 - P(B)
P(A) = P(1) + P(2) +P(3), P(B') = P(1) + P(2)
This holds if P(3) = 0

d. P(A) + P(B) > 1
Can hold if uniformly distributed.
.6+.6 = 1.2

e. P(A) - P(B) < 0
Can hold: P(1) = .1, P(2) = .1, P(3) = .2, P(4) = .3, P(5) = .3
P(A)= .4, P(B)=.8
P(A) - P(B) = -.4

f. P(A) - P(B) > 1
Can not hold. P(A) & P(B) are both between 1 and 0. Using extreme points 1-1 = 0, 0-1 = -1, 1-0 = 1.
 
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