- #1

- 4

- 0

_________

I thought this was a binomial probability distriubtion question, with possibility of success = .4*(2/3) + .8*(1/3) = 8/15

I totaled the probabilities for 3,4, and 5 successes for a 5 examiner group and 2 and 3 successes for a 3 man group and found the probability of success for the 5 man group was higher (.562315 vs .549926), but the book says you have a better chance of passing with a 3 man group.

This is the 2nd question in a row of this type I have screwed up and am desperate to see what I'm doing wrong.