# Problem Calculating a limit with a square root, i'm stuck

Problem Calculating a limit with a square root, i'm stuck :(

## Homework Statement

The limit is equation 9-t / 3-sqrt(t) as t approaches 9

I'm stuck on the how to simplify this?

Thanks for any help.

## The Attempt at a Solution

rock.freak667
Homework Helper

Try multiplying by (3+√t)/(3+√t)

I discovered that that is the conjugate and I came out with this:

27-6sqrt(t)-tsqrt(t)
----------------
9-t

So in other words, that limit does not exist. Is that right?

Mark44
Mentor

The limit does exist. Instead of multiplying by the conjugate over itself, just factor the numerator, treating it as the difference of two squares.