Problem expanding algebraic function via Newton polygon

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The discussion revolves around the challenges of expanding algebraic functions using Newton polygons, particularly when dealing with ramification points that cannot be precisely computed. The original poster, Jack, expresses frustration over the inadequacy of standard methods for expanding around these points, as they often lead to regular expansions instead of capturing the necessary ramified behavior. Responses clarify that the core issue lies in the difficulty of solving high-degree polynomial equations, rather than the substitution method itself, which remains valid. It is noted that while references may highlight these limitations, the nuances of approximating critical points and the implications for convergence are often overlooked. Ultimately, the conversation emphasizes the complexity of polynomial roots and the limitations of existing methods in accurately addressing ramification in expansions.
jackmell
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Hi,

I've run into a problem with expanding algebraic functions via Newton polygons. Consider the function:

f(z,w)=a_0(z)+a_1(z)w+a_2(z^2)w^2+\cdots+a_{10}(z)w^{10}=0

and say the degree of each a_i(z) is ten.

Now suppose I wish to expand the function around some ramification point of the function, say r_i\neq 0

Now, in general, I won't be able to compute exactly that ramification point so that the standard means of expanding around this point, that is, by letting z\to z+r_i and expanding around zero, would seem to fail because I won't be able to exactly compute the new expansion center. That is, the new center of expansion will be slightly off from the ramification point. This point would then be just a regular point and so the algorithm would just compute regular expansions (cycle-1 sheets) when the branching at this point may in fact be ramified.

I just do not understand how it is possible, using this method, to compute ramified power series centered away from zero of not only this function, but any sufficiently high degree function in which the ramification points cannot be computed exactly because of this problem.

Am I missing something with this?

Thanks,
Jack
 
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you seem to be asking how to proceed when you need to know the solution of some polynomial equation of high degree, when such an equation has no obvious solution formula. as far as i know there is no remedy for this. that's why all methods taught in calculus say for integration by partial fractions, e.g. that begin by saying: first find all the roots of this polynomial, are bogus.
 
mathwonk said:
as far as i know there is no remedy for this.

I find this disappointing as all the references I have about Newton polygon suggest making that substitution (z\to z+z_0) to expand the function about the point z_0. Then if there is no solution to this problem, such a substituion in a degree 4 or higher function likely will encounter round-off error and thus fail to pick up the ramifications about z_0 if z_0 is a ramification point -- basically that's saying the method is pretty much useless for expanding high degree functions about ramification points except the origin.

I just cannot believe that's not mentioned anywhere. Not even Walker says anything about this.But thanks for replying. :)

Edit:

Dang it. I re-read some of my reference and this point is in fact emphasized in several of them. For example in:
http://www.lifl.fr/~poteaux/fichiers/monodromy_snc07.pdf
. This fact is not surprising since any close approximation, \overline{c}_k of a critical point c_k is a regular point and expansions above \overline{c}_k have a very small convergence radius
and in fact would lead to incorrect ramifications for c_k. Basically, the calculations have to be done exactly in the standard Newton polygon but there appears to be modified methods which can overcome some of these problems.

Guess I didn't understand before. Sorry guys.
 
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the substitution method is perfectly correct. this problem has nothing to do with that method, nor with Newton polygons. the problem is with solving polynomials.
 
mathwonk said:
the substitution method is perfectly correct. this problem has nothing to do with that method, nor with Newton polygons. the problem is with solving polynomials.

Ok, I understand that now.
 
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this is why we have existence theorems in mathematics. e.g. every polynomial f of odd degree has a root, by the IVT, since f(x) goes to infinity and aLSO TO MINUS INFINITY as |x|-->infinity.

but just try finding the roots of a complicated polynomial of degree 9. all you can do is give an iterative procedure for writing down any finite number of decimals places of a root.

of course it also depends on what you mean by "writing down" a root. if your polynomial has integer coefficients and is irreducible then you could try to work in the field Q[X]/(f), where in fact the root is {X}!

but an element of this field is represented by a vector in nine dimensional Q -space. i.e. an element of this field is represented by a polynomial of degree 8 with rational coefficients.
 

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