Problem in transition from phasor to normal

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nhrock3
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2mrf6f6.jpg


oiler formula says
cosx+isinx

but here they multiply by minus the imaginary part of the phasor representation
the coefficient of sine is minus the imaginary part
why??
 
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nhrock3 said:
oiler formula says
cosx+isinx

That's "Euler" formula. A Frenchman, not a oil tanker. And I suppose you mean the identity

[tex]e^{ix} = \cos x + i\sin x[/tex]

but here they multiply by minus the imaginary part of the phasor representation
the coefficient of sine is minus the imaginary part
why??

I have no idea what your image has to do with your question. Do you mean this? :

[tex]e^{-ix} = \cos{(- x)} + i\sin {(-x)} = \cos x - i\sin x[/tex]
 
LCKurtz said:
That's "Euler" formula. A Frenchman, not a oil tanker. And I suppose you mean the identity

A nitpick: Euler was Swiss, not French.
 
CEL said:
A nitpick: Euler was Swiss, not French.

You are right! And I see upon looking him up, I would also have misspelled his first name had I mentioned it. :redface: