How are phasors obtained from real values in AC?

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SUMMARY

Phasors are derived from real values using Euler's Formula, expressed as ej*(X+phi) = cos(X+phi) + jsin(X+phi). To convert a real value like V(t) = Acos(V+phi) into a phasor representation A PREREQUISITES

  • Understanding of Euler's Formula in complex numbers
  • Knowledge of AC circuit theory and components
  • Familiarity with phasor diagrams and their applications
  • Basic trigonometry related to angles and sine/cosine functions
NEXT STEPS
  • Study the application of Euler's Formula in electrical engineering contexts
  • Learn how to construct and interpret phasor diagrams for AC circuits
  • Explore the differences between series and parallel AC circuits
  • Investigate the implications of phase angles in circuit analysis
USEFUL FOR

Electrical engineers, students studying AC circuit analysis, and anyone interested in the mathematical representation of alternating current systems.

yosimba2000
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Ok, so I know phasors are based on Euler's Formula: ej*(X+phi) = cos(X+phi) + jsin(X+phi)

But how do we use real value like V(t) = Acos(V+phi) in Euler's Formula?

V(t) has no imaginary component, so how can we write the phasor of this as A<phi, where phi is the angle between real and imaginary axis?

I guess what I'm really asking is the "derivation" of real values to another representation that uses imaginary numbers..
 
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For a series circuit, you have to use current as the reference in the circuit, and then express the voltage across each component in degrees relative to that. For a parallel circuit the converse. It can be done graphically if preferred, using a phasor diagram, and this is a good way to understand what is going on.
 

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