- #1

crazyog

- 50

- 0

The Problem:

An air puck of mass (m1) is tied to a string and allowed to revolve in a circle of radius (R) on a frictionless horizontal table. The other end of the string passes througth a hole in the center of the table, and a counterwieght of mass (m2) is tied to it. The suspended object remains in equilibrium while the puck on teh tabletop revolves.

What are (a) the tension in the string, (b) the radial force acting on the puck,

(c) the speed of the puck?

I believe relevant equations include

Tension=(mass)(gravity)

Centripal force= (m1)(v^2)/(r)

T= ((2*m1*m2)/(m1+m2))(g)

Ok for part a)

I understand tension would be T= m2*g for the counterweight. Is there a tension in the other part of the string? (I'm not sure if I fully understand the concept of "tension")

or would I use an equation I found it my book when I was fidning the tension of similar to the Atwood Machine problem - T= ((2*m1*m2)/(m1+m2))(g)

b) I believe this has to do with centripal force. (Is that what they mean by "radial force"?)

Is this the opposite of tension?

c)

I would set (m1)(v^2)/r=m2*g

and I get v=sqrt((m2*g*r)/(m1))

However I was thinking and I'm not sure if the bottom part would be (m1+m2)...

I attached the image in a document for a visual representation.

Any help at all would be appreciated! Thank you!!!

An air puck of mass (m1) is tied to a string and allowed to revolve in a circle of radius (R) on a frictionless horizontal table. The other end of the string passes througth a hole in the center of the table, and a counterwieght of mass (m2) is tied to it. The suspended object remains in equilibrium while the puck on teh tabletop revolves.

What are (a) the tension in the string, (b) the radial force acting on the puck,

(c) the speed of the puck?

I believe relevant equations include

Tension=(mass)(gravity)

Centripal force= (m1)(v^2)/(r)

T= ((2*m1*m2)/(m1+m2))(g)

Ok for part a)

I understand tension would be T= m2*g for the counterweight. Is there a tension in the other part of the string? (I'm not sure if I fully understand the concept of "tension")

or would I use an equation I found it my book when I was fidning the tension of similar to the Atwood Machine problem - T= ((2*m1*m2)/(m1+m2))(g)

b) I believe this has to do with centripal force. (Is that what they mean by "radial force"?)

Is this the opposite of tension?

c)

I would set (m1)(v^2)/r=m2*g

and I get v=sqrt((m2*g*r)/(m1))

However I was thinking and I'm not sure if the bottom part would be (m1+m2)...

I attached the image in a document for a visual representation.

Any help at all would be appreciated! Thank you!!!