Problem question on power calculation

Click For Summary

Homework Help Overview

The discussion revolves around a power calculation problem involving lifting a weight using a block and tackle system. The original poster presents their calculations for power and efficiency based on the given parameters of weight, height, and time.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate power and efficiency using the formulas for work and efficiency, but their results differ from the book's answers. Some participants question the accuracy of the time conversion used in the calculations.

Discussion Status

The discussion is ongoing, with participants exploring the discrepancies between the original poster's calculations and the book's answers. There is a focus on clarifying the time duration for the calculations, with some guidance offered regarding the correct interpretation of the time given in the problem.

Contextual Notes

Participants are discussing the implications of using 60 seconds versus 80 seconds in the calculations, as the problem states the time as "1 minute and 20 seconds." There is also mention of the actual power used being significantly higher than the calculated power.

wewelsburg
Messages
5
Reaction score
0
Here's the question and my answer doesn't match what the book gives as you can see in the below workings out

1)A 300 KG weight is lifted with a block and tackle to a height of 4m in 1 minute and 20 seconds A) Neglecting friction, calculate the power used? B)What’s the efficiency if the actual power used is 24KW?


My working a) Power=work/time To find work firstly force must be found
Force=300 KG X 9.81m/s= 2,943 N
Work=Force X Distance= 2,943 N X 4M=11,772 Joules
Power=11,772/60 seconds=196.2 Watts

B)Efficiency=Power out/Power in X 100
196.2/24000 X 100

Book answers= A)=15W B)=62 percent
 
Physics news on Phys.org
are you sure your data is correct? your working is correct except for the part where you should have put 80 instead of 60 seconds. plus the part about 15 W and 24 KW doesn't match...
 
yep those are the answers the book gives. Why would I divide by 80 seconds and not 60?
 
wewelsburg said:
yep those are the answers the book gives. Why would I divide by 80 seconds and not 60?

Because the work is done "in 1 minute and 20 seconds" = 60sec+20sec = 80sec.
 

Similar threads

Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
6
Views
2K
Replies
18
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K