- #1

- 3

- 0

I don't know if i'm on the right track

Fnet = ma

fnet = Fg+ Fr

Fg = mg

Mg + Fr = ma

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- Thread starter Chosen-wun
- Start date

- #1

- 3

- 0

I don't know if i'm on the right track

Fnet = ma

fnet = Fg+ Fr

Fg = mg

Mg + Fr = ma

- #2

- 912

- 19

[tex]F_r=kv[/tex] where k is constant of proportionality.

[tex]\Rightarrow mg-kv=ma[/tex]

the negative sign is there since the air drag opposes the downward motion,

[tex]\therefore a = g-\frac{kv}{m}[/tex]

- #3

- 3

- 0

[tex]F_r=kv[/tex] where k is constant of proportionality.

[tex]\Rightarrow mg-kv=ma[/tex]

the negative sign is there since the air drag opposes the downward motion,

[tex]\therefore a = g-\frac{kv}{m}[/tex]

That makes a lot more sense, thank you.

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