A Problem Involving Newton's Second Law

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Homework Help Overview

The problem involves a sky-diver experiencing forces due to gravity and air resistance, specifically focusing on how to express acceleration as a function of velocity using Newton's Second Law of Motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the relationship between the forces acting on the sky-diver, particularly questioning the assumption about the drag force being constant rather than proportional to velocity.
  • Some participants discuss the application of Newton's Second Law and the definition of drag force in relation to velocity.

Discussion Status

Participants are actively engaging with the concepts, with some providing definitions and clarifications about the drag force. There is a sense of progress as one participant indicates they were able to work through the problem with the provided definitions, although the details of their solution remain unexplored.

Contextual Notes

The discussion includes a focus on the proportionality of the drag force to velocity, which is a key aspect of the problem that participants are examining. There is also an indication that assumptions about the forces may need to be revisited.

Manni
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Once her chute opens, a sky-diver of mass m is acted upon by a downward force Fg due to gravity, and an upward force Fr due to air resistance. If Fg = mg, where g is gravitational acceleration, and Fr is proportional to velocity v, use Newton’s Second Law of Motion to write acceleration a as a function of velocity v.

Hey guys, I need a help on how to approach this problem. Initially, I assumed Fr = Ff = umg. But the problem states that Fr is proportional to velocity. Help?
 
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Newton's 2nd law is
\sum_i \mathbf{F}_i = m\mathbf{a}What do you get when you apply it to this problem?
 
Proportional meaning, the upward force equals the velocity, times a proportionally constant. Hence the drag force is Fr=bv, where b is a real number and v is velocity.
 
Xyius said:
Proportional meaning, the upward force equals the velocity, times a proportionally constant. Hence the drag force is Fr=bv, where b is a real number and v is velocity.

Thanks Xyius! Using your definition of drag force, I was able to work it out!
 
Glad to hear it! :D!
 
Would you care to explain how you did this?
 

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