Problem with values for a bending moment diagram

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Discussion Overview

The discussion revolves around calculating the bending moment diagram for a simply supported beam subjected to a uniformly distributed load (UDL) and point loads. Participants are addressing the methodology for determining bending moments at specified intervals along the beam, including the effects of various loads.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The original poster describes a simply supported beam with specific loads and seeks assistance in calculating bending moments at 1m intervals.
  • Some participants suggest that the bending moment calculations may be incorrect and recommend reviewing the shear force diagram.
  • One participant emphasizes that the bending moment is derived from the area under the shear force curve, indicating a potential misunderstanding in the original poster's approach.
  • The original poster expresses uncertainty about the correctness of their bending moment values and seeks clarification on their calculations.
  • There is a suggestion that the original poster may not have utilized the shear force diagram correctly in their calculations.

Areas of Agreement / Disagreement

Participants generally agree that the original poster's bending moment calculations are incorrect, but there is no consensus on the specific errors or the correct approach to rectify them.

Contextual Notes

The discussion highlights potential misunderstandings in the application of shear force diagrams to derive bending moments, but does not resolve the specific mathematical errors in the original poster's calculations.

PizzaWizza
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Homework Statement



I have a 5m long simply supported beam, with supports at points 0m and 5m. There's a UDL of 10kNm^-1 from 0m to 4m. It has downward forces acting at 2m (10kN) & 4m (15kN). I need to sketch a bending moment diagram to determine the position & value of the max bending moment. I'm asked to show workings using 1m intervals for bend moment calcs.


Homework Equations



Taking moments from one end to determine upward supports.

The Attempt at a Solution



UDL = 4m x 10kN^-1 = 40kNm^-1 @ 2m (centre of)

Taking moments from Support 1 (R1) = 10x2 + 40x2 + 15x4 = R2 x5

R2 = 160/5 = 32kN. ∴ R1 - 33kN (As the sum of downward forces = 65kN)

I've sketch a shear force diagram that I'm happy with, now to where I'm becoming undone.

Calculating the bending moments for the beam @ 1m intervals

M0 = 0

M1 = 33x1 - (10x0.5x1(UDL)) = 33-5 = 28kN @ 1meter

M2 = 33x2 - (10x1x2(UDL)) - (10x1) = 66-30 = 36kN @ 2meters

M3 = 33x3 - (10x1.5x3(UDL)) - (10x2) = 99-65 = 34kN @ 3meters

M4 = 33x4 - (10x2x4(UDL)) - (10x3) - (15x1) = 132-125 = 7kN @ 4meters

I'm assuming M5 has to be zero. This just doesn't feel right to me. I've got 15kN acting @ 4m and it doesn't seem to be having an effect on the diagram if graphed. I have to be doing something wrong?

Thanks for any help.
 
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You should post you SF diagram.

The BM is the area under the SF curve starting at x = 0. I think you have incorrectly done your integrations of the SF curve for x = 1, 2, 3, and 4 m.
 
Thanks for the feedback. Here's the Shear force diagram.
 

Attachments

  • Shear bend diagram 001.jpg
    Shear bend diagram 001.jpg
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So far, so good. And the bending moments?
 
The bending moments I've highlighted in the original message. They're wrong, I know. I just don't know why?

M1 = 33x1 - (10x0.5x1(UDL)) = 33-5 = 28kN @ 1meter

M2 = 33x2 - (10x1x2(UDL)) - (10x1) = 66-30 = 36kN @ 2meters

M3 = 33x3 - (10x1.5x3(UDL)) - (10x2) = 99-65 = 34kN @ 3meters

M4 = 33x4 - (10x2x4(UDL)) - (10x3) - (15x1) = 132-125 = 7kN @ 4meters
 
PizzaWizza said:
The bending moments I've highlighted in the original message. They're wrong, I know. I just don't know why?

M1 = 33x1 - (10x0.5x1(UDL)) = 33-5 = 28kN @ 1meter

M2 = 33x2 - (10x1x2(UDL)) - (10x1) = 66-30 = 36kN @ 2meters

M3 = 33x3 - (10x1.5x3(UDL)) - (10x2) = 99-65 = 34kN @ 3meters

M4 = 33x4 - (10x2x4(UDL)) - (10x3) - (15x1) = 132-125 = 7kN @ 4meters

Perhaps because you didn't use the shear force diagram correctly?

SteamKing said:
The BM is the area under the SF curve starting at x = 0.

The shear force diagram is constructed, in part, to allow the ready creation of the bending moment diagram.
 
Thanks. I appreciate it and I think it's sank in now :)
 

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